hygiene: what if $awk matches name of function?

We use the "command" command to make sure we are running an
external awk and preprocessor. For instance if someone were
to try "cppawk --awk=quote", that would be targetting the
quote function inside cppawk and not that users Awk program
that happens to be called "quote".

2 files changed, 21 insertions, 0 deletions

diff --git a/cppawk b/cppawk
index 3a2b3c0..35cfffb 100755
--- a/cppawk
+++ b/cppawk
@@ -151,6 +151,22 @@ while [ $# -gt 0 ] ; do
   shift
 done
 
+case $awk in
+  'command '* )
+    ;;
+  * )
+    awk="command $awk"
+    ;;
+esac
+
+case $prepro in
+  'command '* )
+    ;;
+  * )
+    prepro="command $prepro"
+    ;;
+esac
+
 trap 'rm -f $tmp_file' EXIT INT TERM
 
 if [ -n "$awk_file" ] ; then
diff --git a/testcases b/testcases
index 3eb492d..8758398 100644
--- a/testcases
+++ b/testcases
@@ -198,3 +198,8 @@ mawk=1
 ./cppawk --prepro-only --awk=mawk gawk=__gawk__ | grep gawk
 :
 gawk=__gawk__
+--
+36:
+./cppawk --prepro=die --prepro-only x 2>&1 | grep 'not found'
+:
+./cppawk: 1: eval: die: not found